Sign Convention for Spherical Lens
THE PHYSICS CAFE
CHAPTER TEN - LIGHT - REFLECTION
AND REFRACTION
1.20 Sign Convention for
Spherical Lens
For solving problems related to lens, we have to measure all the distances from optical centre, to understand the direction of measurement we takes some conventions is called sign convention.
Assuming origin of Cartesian coordinate
system is concentric with optical centre of lens and the object is placed at
left side of lens so that light ray fall on lens from left-hand side. Then
following conventions are
- All
the distances are measured from optical centre.
- All
the distance measured right sides of the optical centre are taken as
positive.
- All
the distance measured left sides of the optical centre are taken as
negative.
- All
the distance measured above the optical centre (principal axis) is taken
as positive.
- All
the distance measured below the optical centre (principal axis) is taken
as negative.
Hint: If we move from optical
centre/origin, along positive axis, distances are positive and along negative
axis, distances are negative.
1.21 Lens Formula and
Magnification (Derivation not required)
Lens Formula: The relation between position of
object, position of image and focal length of lens
Distance of object from the optical
centre is called Position of object (u)
Distance of image from the optical
centre is called Position of image (v)
Perpendicular distance of object’s head
from the optical centre/principal axis is called Height of object (ho)
Perpendicular distance of image’s head
from the optical centre/principal axis is called
Height of image (hi)
The relation between position of
object, position of image and focal length of lens is called Lens formula
1
1 1
__ =
___ - ___
f v u
Hint: If we replace u
with –u in mirror formula it becomes lens formula
Magnification: Ratio
of height of image to height of object is called Magnification
of lens
It tells that our lens made image how
many times bigger or smaller of the given object. If magnification of a given 2
it means image will be twice taller of object.
Hint: If we replace u
with –u in mirror magnification it becomes lens magnification.
Magnification can be
Negative or Positive.
For real image: u is –ve and v is also +ve
by putting value in above formula we have, m = -ve
or
ho is +ve and hi is –ve
by putting value in above formula we have, m = -ve
For virtual image: u is –ve and v is -ve by
putting value in above formula we have, m = +ve
or
ho is +ve and hi is also
+ve by putting value in above formula we have, m = +ve
From the above discussion, magnification
of real image is always –ve and of virtual image is always +ve
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